36s^2=16

Solution for 36s^2=16 equation:

36s^2=16

We move all terms to the left:

36s^2-(16)=0

a = 36; b = 0; c = -16;
Δ = b2-4ac
Δ = 02-4·36·(-16)
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-48}{2*36}=\frac{-48}{72}
=-2/3
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+48}{2*36}=\frac{48}{72}
=2/3
$